What should be taken away from 3x2-4y2+5xy+20 to obtain-x2-y2+6xy+20
Asked by admin @ in Math viewed by 297 People
What should be taken away from 3x^2-4y^2+5xy+20 to obtain-x^2-y^2+6xy+20
Answered by admin @
Answer:
Let q should be subtracted.
Then according to question,
3x2−4y2+5xy+20−q=−x2−y2+6xy+20
⇒q=3x2−4y2+5xy+20−(−x2−y2+6xy+20)
⇒q=3x2−4y2+5xy+20+x2+y2−6xy−20
⇒q=3x2+x2−4y2+y2+5xy−6xy+20−20
⇒q=4x2−3y2−xy+0
Hence, 4x2−3y2−xy should be subtracted.
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