What must be added to x3 3x2 12x 19
Asked by admin @ in Math viewed by 263 People
What must be added to x^3-3x^2-12x+19so that the result is excatly divisible by x^2+x-6
Answered by admin @
X² + x -6 ) x³ - 3x² -12x + 19 ( x -4
x³ + x² -6x
--------------------------------
-4x² -6x + 19
-4x²-4x + 24
-------------------------------------
-2x - 5
hence ,
x³ - 3x² -12x + 19 = (x² +x - 6)(x - 4) -(2x + 5)
x³ - 3x² -12x + 19 + (2x + 5) = (x² + x - 6)(x - 4)
hence if we add (2x + 5)
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