Three numbers whose sum is 21 are in ap
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three numbers are in A.P whose sum is 21. if 2,2,14 are added to them respectively. the number are in G.P. Find the numbers
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Answer:
Dear student,
Let the numbers in AP be a-d, a, a+d.
It is given that the sum of these numbers is 21.
So, a-d+a+a+d = 21
This gives, a = 7
So, the numbers are 7-d, 7, 7+d.
It is given that if 2, 2, 14 respectively are added to the numbers, then the resulting numbers are in GP.
So, 9-d, 9, 21+d are in GP.
Therefore,
9/9-D =21+d/9
by simplyfying this we get
d^2+12d-108=0
=(d+18)(d-6)=0
d=-18 or 6
Thus, when d = -18, the numbers are 25, 7, -11.
When d = 6, the numbers are 1, 7, 13
Step-by-step explanation: hope it helps you mark my answer as brainlist answer
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