The sum of ages of two friends is 20
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the sum of the ages of two friend is 20. Four years ago, the product of their age in years was 48, Is it possible to determine their present age?
Answered by admin @
Solutions :-
Let age of first friend be x
Sum of age of two friends = 20 years
So, Age of second friend = (20 - x)
Four years ago,
Age of first friend = x - 4
Age of second friend = (20 - x) - 4 = 16 - x
Given : Four years ago, Product of the age of two friends = 48 years
A/q
=> (x - 4) (16 - x) = 48
=> x (16 - x) - 4 (16 - x) = 48
=> 16x - x² - 64 + 4x = 48
=> - x² + 16x + 4x - 64 - 48 = 0
=> - x² +20x - 112 = 0
=> x² - 20x + 112 = 0
Now,
Comparing the equation with ax² + bx + c
a = 1
b = -20
c = 112
We know,
D = b² - 4ac
= (-20)² - (4 × 1 × 112)
= 400 - 448
= - 48
Since,
D < 0 ( No real roots )
Hence,
It is not possible to determine their present age.
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