Asked by admin @ in Math viewed by 315 People
"Question 7 The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m^2 is Rs 4.
Class 8 Mensuration Page 178"
Answered by admin @
Mensuration:
Mensuration is the branch of mathematics which concerns itself with the measurement of Lengths, areas & volume of different geometrical shapes or figures.
Plane Figure: A figure which lies in a plane is called a plane figure.
For e.g: a rectangle, square, a rhombus, a parallelogram, a trapezium.
Perimeter:
The perimeter of a closed plane curve is the total length of the curve.
Unit of perimeter is a unit of length.
Area: the area of the plane figure is the surface enclose by its boundary.
A square centimetre (cm²) is generally taken at the standard unit of an area. We use square metre (m²) also for the units of area.
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Solution:
Given:
d1= 45cm , d2= 30cm
Number of tiles= 3000
Rate per m²= ₹4
Area of Rhombus= 1/2×d1×d2
= (1/2) × 45 × 30=675
Area of 1 tile= 675 cm² = 675/10000 m²
Area of 3000 tiles= 3000 × (675/10000)
[1cm²= 1/10000m²]
cost of Polishing the floor
= Total Area × rate
= (3000 × 675 ×4)/10000
= 3× 675×4/10
= 3× 67.5×4
= 12× 67.5
= ₹ 810
Hence the total cost of polishing the floor
= ₹ 810
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Hope this will help you...
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