The difference of squares of two natural numbers is 45
Asked by admin @ in Math viewed by 320 People
The difference of squares of two natural numbers is 45 . The square of the smaller number is 4 times the larger number.Then the numbers are ?
Asked by admin @ in Math viewed by 320 People
The difference of squares of two natural numbers is 45 . The square of the smaller number is 4 times the larger number.Then the numbers are ?
Answered by admin @
Let the larger number be x and the smaller number be y.
It is given that,
The difference of square of two numbers is 45.
⇒ x² - y² = 45 .... (i)
Also, square of smaller number is four times the larger number.
⇒ y² = 4x
According to the question ;
x² - y² = 45
⇒ x² - 4x = 45 [Since, y² = 4x]
⇒ x² - 4x - 45 = 0
On splitting the middle term,
⇒ x² - (9 - 5)x - 45 = 0
⇒ x² - 9x + 5x - 45 = 0
⇒ x(x - 9) + 5(x - 9) = 0
⇒ (x - 9)(x + 5) = 0
⇒ x = 9 or x = - 5
Thus, by neglecting the negative value
Substituting the value of x in (i)
⇒ x² - y² = 45
⇒ (9)² - y² = 45
⇒ 81 - y² = 45
⇒ y² = 81 - 45
⇒ y² = 36
⇒ y = ± √36
⇒ y = 6 [Neglecting negative value]
Therefore, the required numbers are-
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