Sum of opposite angles of a quadrilateral is 180
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If the sum of pair opposite angles of a quadrilateral is 180 ,than the quadrilateral is cyclic proof
Asked by admin @ in Math viewed by 309 People
If the sum of pair opposite angles of a quadrilateral is 180 ,than the quadrilateral is cyclic proof
Answered by admin @
Answer:
The proof is explained below.
Step-by-step explanation:
Given the sum of pair of opposite angles of a quadrilateral is 180° we have to prove that the quadrilateral is cyclic.
Let us assume that the quadrilateral ABCD is not cyclic i.e Let the point D does not lie on the circle which makes the quadrilateral non-cyclic. Now, let us do a construction such that join CD' where D' is the point of intersection of side AD with the circle.
Now, ABCD' is cyclic
⇒ ∠3 + ∠4 = 180°
Now, it is given that the sum of pair opposite angles of a quadrilateral ABCD is 180°
Therefore, ∠2 + ∠4 = 180°
From above two equations we get
∠3 + ∠4 = ∠2 + ∠4
⇒ ∠3 = ∠2
Now, in triangle CDD', by external angle property
∠3 = ∠1 + ∠2
⇒ ∠1 = 0 , hence the side CD' and CD coincides
⇒ Point D lies on circle
Hence, our supposition is wrong quadrilateral ABCD is cyclic.
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