Solve the question 4 1 2 5 x 437


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Solve the equation ( - 4 ) + ( - 1 ) + 2 + .... + x = 437.

Answered by admin @




\underline{\mathfrak{Solution : }}


\textsf{The above series forms an A.P.}



\mathsf{Where, } \\ \\\\\mathsf{ \implies First \: term(a) \: = \: -4 } \\ \\\\\mathsf{\implies Last \: term (l) \: = \: x } \\ \\\\\mathsf{\implies Common \: difference (d) \: = \: (-1) \: - \: (-4)}  \\  \\ \mathsf{   \qquad \qquad \qquad \qquad  \qquad \qquad  \: = \: -1 \: + \: 4 }\:  \\ \\  \mathsf{ \qquad \qquad \qquad \qquad \qquad \qquad \: = \: 3 }


\mathsf{Let, no. \: of \: terms \: is \:  n.  }




\mathsf{Using \: Formula, } \\ \\\\\mathsf{ \implies l \: = \: a \: + \: (n \: - \: 1)d } \\ \\\\\mathsf{\implies x \: = \: (-4) \: + \: (n \: - \: 1)3 } \\ \\\\\mathsf{\implies x \: = \: -4 \: + \: 3n \: - \: 3 } \\ \\\\\mathsf{\implies x\: = \: 3n \: - \: 7 } \\ \\\\\mathsf{\implies x\: + \: 7 \: = \: 3n } \\ \\\\\mathsf{\therefore \quad n \: = \: \dfrac{( x \: + \: 7)}{3}}



\underline{\mathsf{Now, }} \\ \\\\\mathsf{\implies S_{n} \: = \: \dfrac{n}{2}( a \: + \: l )}  \\ \\\textsf{Plug the value of \textbf{n}, } \\  \\  \\ \\\mathsf{\implies 437 \: = \: \dfrac{ \quad(\dfrac{x\: + \: 7}{3}) \quad}{2}( -4 \: + \: x )}




 \\ \mathsf{\implies 437 \: \times \: 2 \: = \: \dfrac{(x \: + \: 7)}{3}(x \: - \: 4 )} \\ \\\\\mathsf{\implies 437 \times \: 2 \: \times \: 3 \: = \: (x \: + \: 7 )( x \: - \: 4 )}


 \\ \mathsf{\implies 2622 \: = \: {x}^{2} \: - \: 4x \: + \: 7x \: - \: 28 }  \\  \\  \mathsf{ \implies  {x}^{2} \:  +  \: 3x \:  -  \: 28 \:  -  \: 2622  \:  =  \: 0 } \\  \\  \mathsf{ \implies  {x}^{2}  \:  +  \: 3x \:  -  \: 2650 \:  =  \: 0}



\mathsf{Here, } \\ \\\\\mathsf{\implies Coefficient \: of \: {x}^{2}(a) \: = \: 1 } \\ \\\\\mathsf{\implies Coefficient \: of \: x (b ) \: = \: 3 } \\ \\\\\mathsf{\implies Constant \: term(c) \: = \: -2650 }



\textsf{Using Quadratic  Formula , }  \\  \\  \mathsf{ \implies x \:  =  \:  \dfrac{ - b \:  \pm \: \sqrt{  \: {b}^{2} \:  -  \: 4ac \:  } }{2a} }


  \\ \mathsf{ \implies x \:  =  \:  \dfrac{ - 3 \:  \pm \:  \sqrt{ \: ( {3}^{2} ) \:  -  \: 4 \:  \times  \: 1 \:  \times  \: ( - 2650)} }{2 \:  \times  \: 1} } \\  \\  \\  \mathsf{ \implies x \:  =  \:  \dfrac{ - 3 \:  \pm \:  \sqrt{ \: 9 \:  +  \: 10600} }{2}}




  \\ \mathsf{ \implies x \:  =  \:  \dfrac{ - 3 \:  \pm \:  \sqrt{ \: 10609} }{2} } \\  \\  \\  \mathsf{ \implies x \:  =  \:  \dfrac{ - 3 \:  \pm \: 103}{2}}



  \\ \mathsf{\implies x \: = \: \dfrac{-3 \: + \: 103}{2} \quad, \implies x \: = \: \dfrac{-3 \: - \: 103}{2}} \\ \\ \\\\\mathsf{\implies x \: = \: \dfrac{100}{2} \quad, \implies x \: = \: \dfrac{-106}{2}} \\ \\ \\\\\mathsf{\implies x \: = \: 50 \: or \: (-53 ) \: [ Not \: Possible ]}



\boxed{\underline{\mathsf{Therefore, x \: is \: equal \: to \: 50.}}}



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