Sides ab and ac of triangle abc are extended


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"Question 2 In the given figure sides AB and AC of ΔABC are extended to points P and Q respectively. Also, ∠PBC < ∠QCB. Show that AC > AB.

Class 9 - Math - Triangles Page 132"

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Linear pair of angles:

If Non common arms of two adjacent angles form a line, then these angles are called linear pair of angles.



Axiom- 1

If a ray stands on a line, then the sum of two adjacent angles so formed is 180°i.e, the sum of the linear pair is 180°.


Axiom-2

If the sum of two adjacent angles is 180° then the two non common arms of the angles form a line.


The two axioms given above together are called the linear pair axioms.


____________________________________

Use the Inequality that the side opposite to the larger angle is longer, to show the inequality.


____________________________________


Given: ∆ABC is a Triangle &

∠PBC < ∠QCB


To Prove:

AC>AB



Proof:


∠ABC + ∠PBC = 180°
( by linear pair axiom)
⇒ ∠ABC = 180° – ∠PBC


also,

∠ACB + ∠QCB = 180°
(by Linear Pair axiom)
⇒ ∠ACB = 180° – ∠QCB


Since,

∠PBC < ∠QCB therefore, ∠ABC > ∠ACB


Here, the side opposite to the larger angle is longer.


Hence, AC > AB


========================================

Hope this will help you.....

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