Answer:
The height of the tower is 3√3 m & the height of the flag mounted on it is 6√3 m .
Step-by-step explanation:
Let the height of the flag-pole (AD) be x & height of tower (AB) be h .
Angle of elevation 9 m away from the foot of the tower to the top of the flag-pole , ∠BCD = 60° & angle of elevation to the bottom of the flag-pole , ∠ACB = 30°
Let BC = 9 m
In right triangle , ∆ABC,
tan 30° = P/B = AB/BC
1/√3 = h/9
√3 h = 9
h = 9/√3
h = (9 ×√3) /(√3 × √3)
[On Rationalising]
h = 9√3/3
h = 3√3
Height of the tower ,h = 3√3 m ……….(1)
In right triangle , ∆DBC,
tan 60° = P/H = DB/BC
tan 60° = (AD + AB)/BC
√3 = (h + x)/9
9√3 = (h + x)
9√3 = 3√3 + x
[From eq 1]
9√3 - 3√3 = x
x = 6√3
Height of the flag mounted on it = 6√3 m
Hence, the height of the tower is 3√3 m & the height of the flag mounted on it is 6√3 m .
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