Length of the fence of a trapezium shaped field


Asked by admin @ in Math viewed by 252 People


"Question 3 Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

Class 8 Mensuration Page 178"

Answered by admin @



Mensuration:

Mensuration is the branch of mathematics which concerns itself with the measurement of Lengths, areas & volume of different geometrical shapes or figures.

Plane Figure: A figure which lies in a plane is called a plane figure.

For e.g:  a rectangle, square, a rhombus, a parallelogram, a trapezium.

 

Perimeter:

The perimeter of a closed plane figure is the total length of its boundary.

In case of a triangle or a polygon the perimeter is  the sum of the length of its sides.

Unit of perimeter is a centimetre  (cm), metre(m) kilometre(km) e.t.c


Area: The area of the plane figure is the measure of the surface enclose by its boundary.

 

The area of a triangle are a polygon is the measure of the surface enclosed by its sides.

A square centimetre (cm²) is generally taken at the standard unit of an area. We use square metre (m²) also for the units of area.

==========================================================

Solution;

Given:


Length of the fence of a trapezium ABCD =120
m.  BC = 48 m, CD = 17 m and AD = 40 m,

 

Length of the
fence of a trapezium ABCD =AB +BC+ CD+ AD

120=AB +
48+17+40

120 = AB + 105

120 – 105 = AB

AB= 15 m

Height (AB) = 15
m

 

Area of
Trapezium


= 1/2 x sum of parallel sides x perpendicular
distance



Area of Trapezium

= (1/2) (48+40) 15

= ½(88)(15)

= 44× 15

=660 m²


Hence, the area
of the field = 660 m²

==========================================================

Hope this will help you...


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