In fig 8.13 find tan p cot r


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Question 2 In the given figure find tan P − cot R

Class 10 - Math - Introduction to Trigonometry Page 181

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Heya bhaiya here is your answer

using Pythagoras law we got

QR² = PR² - PQ²

=> QR = √ PR² - PQ²

=> QP = √ ( 13 )² - ( 12 )²

=> QP = √ 169 - 144

=> QP = √25

=> QP = 5


.°. tan P = QR/PQ

tan P = 5/12

and

Cot R = QR/PQ

Cot R = 5/12

now

tan P - Cot R

= 5/12 - 5/12

= 0

answer is nothing means 0 ! xD

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