If the prime factorization of a natural number n is
Asked by admin @ in Math viewed by 297 People
if the prime factorization of a natural number n is 2^3 x 3^2 x 5^2 x 7, then the number of consecutive zeroes are?
Asked by admin @ in Math viewed by 297 People
if the prime factorization of a natural number n is 2^3 x 3^2 x 5^2 x 7, then the number of consecutive zeroes are?
Answered by admin @
Answer:
The given expression 'n' has only 2 consecutive zeroes.
Solution:
Given that
The prime factorization of the given natural number n is 2^3× 3^2×5^2× 7
Prime factorization: by using prime factorization we can find out which prime numbers multiple together to make the original number.
To find the consecutive zeroes in a number, split out the 2’s and 5’s which can finally sum up together to give 10.
Thus, in the given natural number 'n' there are 2 consecutive zeroes.
Asked by admin @ in Math viewed by 337 persons
Asked by admin @ in Math viewed by 455 persons
Asked by admin @ in Math viewed by 350 persons
Asked by admin @ in Math viewed by 332 persons
Asked by admin @ in Math viewed by 337 persons
Asked by admin @ in Math viewed by 263 persons
Asked by admin @ in Math viewed by 463 persons
Asked by admin @ in Math viewed by 426 persons
Asked by admin @ in Math viewed by 280 persons
Asked by admin @ in Math viewed by 302 persons
Asked by admin @ in Math viewed by 294 persons
Asked by admin @ in Math viewed by 389 persons
Asked by admin @ in Math viewed by 361 persons
Asked by admin @ in Math viewed by 337 persons
Asked by admin @ in Math viewed by 292 persons
Asked by admin @ in Math viewed by 12034 persons
Asked by admin @ in Math viewed by 11518 persons
Asked by admin @ in Math viewed by 11506 persons
Asked by admin @ in Math viewed by 4178 persons