Find two solutions of the equation 4x 3y 12


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Find two solutions for the equation 4x+3y=12

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Answer:

Given equation is 4x+3y =12

case 1. When X = 0 we get

3y = 12

therefore y = 4

then (0,4) is the first solution.

and case.2 When Y =0

we get 4x = 12

therefore x = 3

therefore  (0, 3) is the second solution

Hence (0,4) and (0, 3) are the two solution.


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