Find the least number which when divided by 6 15

Asked by admin @ 03/08/2021 in Math viewed by 256 People

Find the least number which when divided by 6, 15, 18 leave remainder 5 in each case

Answered by admin @ 03/08/2021

Solution :-

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.

L.C.M. of 6, 5 and 18

6 = 2*3
15 = 3*5
18 = 2*3*3

L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90

Now,
5 + 90 = 95

Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.

Let us check our answer.

1) 95/6
Quotient = 15
Remainder = 5

2) 95/15
Quotient = 6
Remainder = 5

3) 95/18
Quotient = 5
Remainder = 5

So, the required number is 95.

Answer.

<div data-test="answer-box-text" class="sg-text sg-text--break-words brn-rich-content js-answer-content"> <span>we have to find how much is the value of 2 in one number greater than the same value in another number. in the number 2,783 the value 2 represents 2,000 and in the number 7,283 the value 2 represents 200. so : 2,000 : 200 = 10. answer: the value 2 in 2,783 is 10 times the value of 2 in 7,283.</span><br /> </div>

Asked by maham237 @ 14/01/2021 in Biology viewed by 426 persons

Find the least number which when divided by 6 15

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