Cos 6a sin 6a 1 3 sin 2a cos 2a


Asked by admin @ in Math viewed by 320 People


Prove that
sin^6A+cos^6A = 1- 3sin^2Acos^2A

Answered by admin @



Sin^6A+cos^6A
(sin²A)³+(cos²A)³ ............[a^6=(a²)³]
(sin²A+cos²A)³-3sin²Acos²A.........[(a+b)³=a³+b³+3ab]
1³-3sin²Acos²A
1-3sin²Acos²A

!!hence proved!!


 



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