Centre 1 2 1 4 and radius 1 12
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Question 3 Find the equation of the circle with centre (1/2, 1/4) and radius 1/12
Class X1 - Maths -Conic Sections Page 241
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Concept : if (h,k) is the centre of cirlce and r is the radius of that circle then, equation of cirlce is (x - h)² + (y -k)² = r²
here,
Centre of circle = ( 1/2 , 1/4)
radius of cirlce = 1/12
equation of circle is
(x - 1/2)² + (y - 1/4)² = (1/12)²
x² + 1/4 - x + y² + 1/16 - y/2 = 1/144
x² + y² - x -y/2 + 1/4 + 1/16 - 1/144 = 0
x² + y² - x - y/2 + (36 + 9 -1)/144 = 0
x² + y² - x - y/2 + (44)/144 = 0
x² + y² - x -y/2 + 11/36 = 0
36x² + 36y² -36x - 18y + 11= 0
hence, equation of cirlce is , 36x² + 36y² -36x - 18y + 11 = 0
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