Ax 4 bx 3 cx 2 dx e 0
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How to solve ax^4+bx^3+cx^2+dx+e
Answered by admin @
Ax⁴ + bx³ +cx² +dx +e is 4th degree polynomial e.g byquadratic polynomial.
we can't find exactly what is the roots of given polynomial . but at least one roots given then we find out by relation between roots and coefficient .
here ax⁴ + bx³ +cx² +dx+e is given polynomial let A , B, C and D are the roots of this .then,
A + B + C + D = -b/a
(A + B)( C + D) + AB + CD = c/a
AB(C+D) +CD(A +B) = -d/a
ABCD = e/a
Let ∅ is roots of given polynomial given then question ask find another roots of this polynomial.
then, you should be use relation.
you will have four equation and three variable then solution possible. i know its complicated . but I think this is one option for finding roots when directly factorisation not possible .
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