An increase of 20 in the price of mangoes

Asked by admin @ 13/08/2021 in Math viewed by 301 People

An Increase of 20% in the price of mangoes enables a person to purchase 4 mangoes less for Rs.40 The price of 15 mangoes before increase was...

Answered by admin @ 13/08/2021

The price of 15 mangoes before increase was Rs. 25

Explanation

Lets assume, the original price of each mango before the increase was Rs. X

So, the number of mangoes the person can buy for Rs. 40 was = $\frac{40}{X}$

Now the price of each mango is increased by 20%. So, the recent price of each mango will be $=X+(X*0.20) = X+ 0.2X = 1.2X$

So, the number of mangoes for Rs. 40 will be : $\frac{40}{1.2X}$

According to the question, this number of mangoes is 4 less than the number of mangoes before price increase. So..

$\frac{40}{X}-\frac{40}{1.2X} = 4 \\ \\ \frac{(40*1.2)-40}{1.2X}=4\\ \\ \frac{48-40}{1.2X}=4\\ \\ \frac{8}{1.2X} =4\\ \\ 4*1.2X=8\\ \\ 4.8X=8\\ \\ X= \frac{8}{4.8}\\ \\ X=\frac{80}{48}=\frac{5}{3}$

So, the original price of each mango was Rs. $\frac{5}{3}$

Thus, the price of 15 mangoes before increase was:

Rs. $\frac{5}{3}*15$

= Rs. $25$

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An increase of 20 in the price of mangoes

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