Abcd is a trapezium with ab parallel to cd


Asked by admin @ in Math viewed by 361 People


ABCD is a trapezium in which AB is parallel to CD and AD is equal to BC. show that angle A is equal to angle B. angle C equal to angle D. triangle ABC is congruent to triangle BAD and diagonal AC equal to diagonal BD

Answered by admin @



Hi friend!


Construction: Draw a line through C parallel to DA

intersecting AB produced at E.


Proof:


i)


AB||CD(given)


AD||EC (by construction)


So ,ADCE is a parallelogram



CE = AD

(Opposite sides of a parallelogram)




AD = BC (Given)


We know that ,


∠A+∠E= 180°


[interior

angles on the same side of the transversal AE]


∠E= 180° - ∠A


Also, BC = CE

∠E = ∠CBE= 180° -∠A


∠ABC= 180° - ∠CBE


[ABE  is a straight line]


∠ABC= 180° - (180°-∠A)


∠ABC= 180° - 180°+∠A


∠B= ∠A………(i)


 


(ii) ∠A + ∠D = ∠B + ∠C = 180°


 (Angles on

the same side of transversal)



∠A + ∠D = ∠A + ∠C


 (∠A = ∠B) from eq (i)



 ∠D = ∠C


 


(iii) In ΔABC and ΔBAD,


AB = AB (Common)

∠DBA = ∠CBA(from eq (i)


AD = BC (Given)



ΔABC ≅ ΔBAD


 (by SAS congruence rule)




(iv)  Diagonal AC = diagonal BD


 (by CPCT as ΔABC ≅ ΔBAD)

Hope this helps!


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