Hi there !
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Solution :
On the first Sunday morning at 8 : 00 a.m. , the watch is 5 min slow, and next Sunday at 8 : 00 p.m. , it becomes 5 min 48 secs fast.
So, the watch gains
Hence,
To show the correct time, it must have to gain 5 min .
5 min --) are gained in ( 180 × 5 / 54 × 5)
=> 83 hours 20 min = 3 days 11 hours 20 min.
Watch is correct 3 days 11 hours 20 min. after 8 am of Sunday.
Hence,
The watch will be correct at 20 min past at 7 p.m. on Wednesday.
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Thanks for the question !