A three digit number is equal to 17 times


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A three digit number is equal to 17 times the sum of its digit; if the digits reversed, the new number is 198 more than the old number; also the sum of extreme digits is less than the middle digit by unity. find the original number by using the method of linear ewuation in two variables

Answered by admin @



Answer:

153

Step-by-step explanation:

let the hundred place digit be x , tens digit be y and unit digit be z

So Number = 100x+10y+z

We are given that A three digit number is equal to 17 times the sum of its digit

 100x+10y+z = 17(x+y+z)

 100x+10y+z = 17x + 17y + 17z

100x-17x+10y-17y+z-17z = 17x + 17y + 17z

83x -7y -16z = 0-----------------------(1)

if the digits reversed, the new number is 198 more than the old number

100x+10y+z + 198 = 100z + 10y + x

100x- x +10y-10y +z - 100z +198 = 0

99x - 99z+198 = 0

 z-x=2

 z = x + 2----------------------------(2)

the sum of extreme digits is less than the middle digit by unity.

And,  

z + x = y-1

By putting (2)

z+z-2=y-1

 y = 2z-1                                                       ----------------------------(3)

Putting (3) and (2) in (1) we get

 83(z-2) -7(2z-1) -16z = 0

 83(z-2) -7(2z-1) -16z = 0

z = 3

put z = 3 in (3)

y = 2(3) -1

y = 5

Put z = 3 in (2) 

x = 3-2=1

So. number = 100(1) + 10(5)  + 3 = 153

So, number = 153

Hence the number is 153


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