A number when divided successively by 4 and 5


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q 38. a number when divided successively by 4 and 5 leaves remainder 1 and 4 respectively. when it is successively divided by 5 and 4, then the respective remainders will be;

Answered by admin @



The options for this question are missing: here are the options:

A. 1,2


B. 2, 3


C. 3, 2


D. 2,1

Solution:

Let P be the number

Given that

P ÷ 4 = Q, remainder = 1

Q ÷ 5 = 1, remainder = 4

Hence Q = 1 × 5 + 4 = 9

P = 4Q + 1 = (4 × 9) + 1 = 36 + 1 = 37

Now we will divide 37 successively by 5 and 4

37 ÷ 5 = 7, remainder = 2

7 ÷ 4 = 1, remainder = 3

The correct answer is option B


B. 2, 3


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