Dissolving 120g of urea in 1000g of water
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the density of a solution prepared by dissolving 120g of urea in 1000g of water is 1.15g/ml .find the molarity & molality of this solution
Answered by admin @
Molarity = Number of moles of solute/Volume of solution in Litres
Moles of urea = Given mass/Molecular mass = 12060 = 2 mol
Volume of solution = Mass of solution/Density of solution= (120+1000) g/1.15 g.mL−1= 974 ml or 0.974 L
Hence, Molarity = 2 mol/0.974 L = 2.05 mol L−1
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