1.
mass of NaOH = 20g
volume of solution = 200 ml
m by v % = Mass of solute / volume of solution × 100
==> m by v % = 20/200 × 100
==> m by v % = 10 %
2.
molar mass of KCl = 39.05 + 35.5 ==> 74.55 g
mass of KCl = 0.5 × 74.55 ==> 37.275 g
volume of solution = 200 ml
m by v % = mass of solute / volume of solution × 100
m by v % = 37.275/200 × 100
==> m by v % = 37.275/2
==> m by v % = 18.63 %
3.
mass of NaOH = 40g
volume of solution = 100 ml
m by v % = mass of solute / mass of solution × 100
m by v % = 40/100 × 100
==> m by v % = 40 %
4.
mass of KOH = 20g
volume of solution = 200 ml
m by v % = mass of solute / volume of solution × 100
==> m by v % = 20/200 × 100
==> m by v % = 10 %
From the above calculations,
(1) and (4) will have same concentration.