What type of bond is this combination likely to form

Asked by maham237 @ 18/07/2021 in Chemistry viewed by 425 People

Part 1: Ionic Bonding 1. Choose Sodium (Na). a. What type of element is it? b. How many valence electrons does it have? 2. Choose Fluorine (F). a. What type of element is it? b. How many valence electrons does it have? 3. Answer the question on the screen, "What type of bond is this combination likely to form?" a. Circle: Ionic or Covalent? b. Choose the appropriate number of atoms to make the bond. Record the number of each atom below: 4. Watch the final animation closely (it will play continuously). a. Describe the change in the number of valence electrons in the atoms as the bond is successfully formed: b. What does the positive (+) charge indicate (mention specific subatomic particles in your answer)? c. What does the negative (-) charge indicate (mention specific subatomic particles in your answer)? d. Record the name and molecular formula for the compound below:

Answered by maham237 @ 18/07/2021

Answer:

Explanation:

Sodium is a group 1 element with atomic number 1. It has 11 electrons. It is soft reactive metal. It has 1 valence electron.

Fluorine is a group 7 element, a hologen with 7 valence electron. It is a most reactive non metal.

When sodium react with fluorine, ionic bond is formed in the resulting compound sodium fluoride.

One sodium and fluorine each totaling 2 atoms are enough to make the bond.

As the bond is formed, both atoms have octet structure. That is they each have 8 electrons on their outermost shells.

The positive charge on sodium indicates that sodium had lost 1 electron to fluorine atom.

The negative charge on fluorine ion indicates that fluorine atom had gained 1 electron from sodium atom to form negative ion.

The name of the compound is sodium fluoride with formula NaF.

What type of bond is this combination likely to form

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