What is the oxidation state of each element in k2cr2o7
Asked by admin @ in Chemistry viewed by 282 People
What is the oxidation state of each element in k2cr2o7?
Answered by admin @
To begin this, you'll first note down the valencies of atoms you're sure about.
K is always 1+
And O is always 2-, except for in peroxide where it is 1-.
So now you must remember that a compound is always neutral. Your net charge has to be 0.
K2Cr2O7.
K2 (1+ x 2) = 2+
Cr (2x) = 2x
O7 (2- ×7) = 14-
+2 +2x + (-14) = 0
•Simple algebra.
2x -12 = 0
2x = 12
x = +6.
Each Cr atom has an oxidation number of +6.
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