What element forms an ion with an electronic configuration of [kr] and a –2 charge?

Asked by maham237 @ 16/12/2020 in Chemistry viewed by 300 People

Give the symbol for the element?

Answered by maham237 @ 16/12/2020

Answer : The symbol of the element is Selenium (Se).

Explanation :

Electronic configuration is distribution of electrons in an atom in atomic orbitals.

The electronic configuration of [Kr] = $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}$

Total number of electrons in [Kr] = 36

Due to -2 charge, 2 electrons are withdrawn from the electronic configuration of [Kr].

Now the total number of electrons left = 36 - 2 = 34

And the Selenium[Se] is the element which has 34 number of electrons.

Electronic configuration of [Se] = $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{4}$

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