The number of faradays required to deposit 1g equivalent

Asked by admin @ 20/08/2021 in Chemistry viewed by 285 People

The number of Faraday required to deposit 1g equivalent of aluminium (at. Wt. 27) from a solution of AlCl3 is?

Answered by admin @ 20/08/2021

Final Answer : 1 F

Steps:
1) 1-g Equivalent = Mass of substance equal to 1 -equivalent of given chemical species.
Here,
1 - g equivalent of Al has mass 27 / 3 =9 g

2) We have Reaction :

$Al^{3+} (aq.) + 3e^{-} \:\:\: -\ \textgreater \ Al (s) \\ \\ \frac{Q}{F} = 3 =\ \textgreater \ Q=3F \\$

Therfore,
By Faradays Law of Electrolysis,
3 F of charge is required to deposit 1 mole of Al(s).
=> 3F of charge is required to deposit 27 g of Aluminium.
=> 1 F of charge is required to deposit 9 g of Aluminium .
=> 1 F of Charge is required to deposit 1- g equivalent of Aluminium.

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