The largest number of hydrogen atoms present in


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Maximum no. of hydrogen atoms are in:

(A) 16g of CH4(B) 31.2g of C6H4 (C) 34.2g of C12H22011.(D) 36g of CoH1206​

Answered by admin @



Answer: The correct answer is Option B.

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    .....(1)

  • For Option A:

Given mass of methane = 16 g

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane}=\frac{16g}{16g/mol}=1mol

1 mole of methane compound is formed by 1 mole of carbon and 4 moles of hydrogen atoms.

According to mole concept:

1 mole of a gas contains 6.022\times 10^{23} number of atoms.

So, 1 mole of methane compound will have 4\times 1\times 6.022\times 10^{23}=24.088\times 10^{23} number of hydrogen atoms.

Number of hydrogen atoms = 24.088\times 10^{23}

  • For Option B:

Given mass of C_6H_4 = 31.2 g

Molar mass of C_6H_4 = 76 g/mol

Putting values in equation 1, we get:

\text{Moles of }C_6H_4=\frac{31.2g}{76g/mol}=0.41mol

1 mole of C_6H_4 compound is formed by 6 moles of carbon and 4 moles of hydrogen atoms.

According to mole concept:

1 mole of a gas contains 6.022\times 10^{23} number of atoms.

So, 0.41 mole of C_6H_4 compound will have 4\times 0.41\times 6.022\times 10^{23}=9.876\times 10^{23} number of hydrogen atoms.

Number of hydrogen atoms = 9.876\times 10^{23}

  • For Option C:

Given mass of C_{12}H_{22}O_{11} = 34.2 g

Molar mass of C_{12}H_{22}O_{11} = 342.3 g/mol

Putting values in equation 1, we get:

\text{Moles of }C_{12}H_{22}O_{11}=\frac{34.2g}{342.3g/mol}=0.099mol

1 mole of C_{12}H_{22}O_{11} compound is formed by 12 moles of carbon, 22 moles of hydrogen atoms and 11 moles of oxygen atoms.

According to mole concept:

1 mole of a gas contains 6.022\times 10^{23} number of atoms.

So, 0.099 mole of C_{12}H_{22}O_{11} compound will have 22\times 0.099\times 6.022\times 10^{23}=13.116\times 10^{23} number of hydrogen atoms.

Number of hydrogen atoms = 13.116\times 10^{23}

  • For Option D:

Given mass of C_{6}H_{12}O_{6} = 36 g

Molar mass of C_{6}H_{12}O_{6} = 180.156 g/mol

Putting values in equation 1, we get:

\text{Moles of }C_{6}H_{12}O_{6}=\frac{36g}{180.156g/mol}=0.199mol

1 mole of C_{6}H_{12}O_{6} compound is formed by 6 moles of carbon, 12 moles of hydrogen atoms and 6 moles of oxygen atoms.

According to mole concept:

1 mole of a gas contains 6.022\times 10^{23} number of atoms.

So, 0.199 mole of C_{6}H_{12}O_{6} compound will have 12\times 0.199\times 6.022\times 10^{23}=14.38\times 10^{23} number of hydrogen atoms.

Number of hydrogen atoms = 14.38\times 10^{23}

Hence, the correct answer is Option B.


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