The density of 3 molal solution of naoh

Asked by admin @ 31/08/2021 in Chemistry viewed by 292 People

The density of 3 molal solution of NaOH is 1.110 g/ml . Calculate the molarity of the solution.

Answered by admin @ 31/08/2021

Find Molarity , given Molality.

Molality = b = 3
mass density of Sodium Hydroxide solution = ρ = 1.110 gm/ml
ρ = 1.110 kg/Litre
M = Molar mass of Sodium Hydroxide NaOH = 40 = (23+16+1)
= 40 gm/mole = 0.040 kg/mole
Molarity = c = ??

Formula for calculating Molarity given Molality:

c = ρ * b / [1 + b M ]
= 1.110 kg/L * 3 mole/kg / [ 1 + 3 mole/kg * 0.040 kg/mole ]
= 3.330 /(1.12)
= 2.97 Molar

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