The atomic mass of a metal m is 56


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assume that atomic weight of a metal 'M' to be 56,find the empirical formula of its oxide containing 70% of M

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Atomic weight of metal M = 56
in an oxide,  metal is  70% by mass        and so  oxygen is 30% by mass.
let there be  n atoms of  oxygen per 1 atom of metal.
Then  proportion of the masses of metal and oxygen : 
             56 :  n * 16  = 70  : 30
           16 n = 56 * 30 / 70
                 n = 24/16 = 1.5

There are two atoms of metal for 3 atoms of Oxygen.:        M2 O3


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