Solid sodium reacts violently with water producing heat hydrogen gas and sodium hydroxide

Asked by maham237 @ 02/12/2020 in Chemistry viewed by 318 People

How many molecules of hydrogen gas are formed when 48.7 g of sodium are added to water?. 2Na + 2H2O --> 2NaOH + H2. . Show your work.

Answered by maham237 @ 02/12/2020

Answer: 1.06 moles of molecules = 6.38x10²³ molecules

Explanation:

1) Balanced chemical equation:

2Na + 2H₂O -> 2NaOH + H₂

2) Mole ratios:

2 mol Na : 2 mol H₂O : 2 mol NaOH : 1 mol H₂

3) Convert 48.7 g of sodium to moles:

number of moles = mass in grams / molar mass

molar mass of Na = atomic mass = 23.0 g/mol

number of moles = 48.7g / 23.0 g/mol = 2.12 moles of Na

4) Proportion:

2moles Na/1mol H₂ = 2.12 moles Na / x

x = 2.12 moles Na * 1 mol H₂ / 2 moles Na = 1.06 moles H₂.

5) If you want to convert that to number of molecules you have to multiply by Avogadro's number: 6.022 x 10^²³

1.06 mol x 6.022x10^²³ molecules/mol = 6.38x10²³ molecules

Solid sodium reacts violently with water producing heat hydrogen gas and sodium hydroxide

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