How many milliliters of a 0.184 m nano3 solution contain 0.113 moles of nano3?

Asked by maham237 @ 26/12/2020 in Chemistry viewed by 289 People

ans:614 mL

Answered by maham237 @ 26/12/2020

C=0.184 mol/L
n=0.113 mol

n=CV

V=n/C

V=0.113/0.184=0.614 L = 614 mL

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