How does the rate of formation of o2 compared with

Asked by admin @ 30/11/2021 in Chemistry viewed by 283 People

Given the following balanced equation, determine the rate of reaction with respect to [O2]. If the rate of formation of O2 is 7.78 x 10-1 M/s, what is the rate of the loss of O3? 2 O3(g) → 3 O2(g)

Answered by admin @ 30/11/2021

Answer: The rate of the loss of $O_3$ is 0.52M/s

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$2O_3(g)\rightleftharpoons 3O_2(g)$

Rate of disappearance of $O_3$ = $-\frac{1d[O_3]}{2dt}$

Rate of formation of $O_2$ = $+\frac{1d[O_2]}{3dt}$

$-\frac{1d[O_3]}{2dt}=+\frac{1d[O_2]}{3dt}$

Rate of formation of $O_2$ = $7.78\times 10^{-1}M/s$

Thus Rate of disappearance of $O_3$ = $\frac{2d[O_2]}{3dt}=\frac{2}{3}\times 7.78\times 10^{-1}M/s=0.52M/s$

How does the rate of formation of o2 compared with

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