Henry's law constant for co2 in water is 1.67

Asked by admin @ 12/08/2021 in Chemistry viewed by 276 People

Henry’s law constant for CO2 in water is 1.67 × 10 8 Pa at 298 K. Calculate the quantity of CO2 in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K.

Answered by admin @ 12/08/2021

Answer :

Given,

$K_{H} = 1.67 \times 10^{8}$ Pa

Pressure of $Co_{2}$ , ρ $co_{2}$ = 2.5 atm = 2.5 × 101325 Pa

ρ $co_{2}$ = $K_{H}$ × χ $co_{2}$

⇒ χ $co_{2}$ = $\frac{ρco_{2}}{K_{H}}$ = $\frac{2.5 × 101325 Pa}{1.67 × 10^{8} Pa}$

χ $co_{2}$ = 1.517 × $10^{-3}$

⇒ $^{η}co_{2}$ = $\frac{^{η}co_{2}}{^{η}CO_{2} + ^{η}H_{2}O}$

⇒ $\frac{^{η}co_{2}}{^{η}H_{2}O}$ = 1.517 × $10^{-3}$

[ ∵ $^{η}CO_{2}$ < < < $^{η}H_{2}O$ ]

∴ It can be neglected in the denominator.

⇒ $\frac{\dfrac{^{η}CO_{2}}{\ 500}}{18}$ = 1.517 × $10^{-3}$

⇒ $^{η}co_{2}$ = $\frac{500}{18} \times 1.517 \times 10^{-3}$

= $\frac{7.585}{18} \times 10^{-1} = \frac{75.85}{18} \times 10^{-2}$

= 4.214 × $10^{-2}$ moles

= 42.14 × $10^{-3}$ moles

= 42.14 millimoles

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