Francium freezing point
Asked by maham237 @ in Chemistry viewed by 326 People
For a 0.50 molal solution of sucrose in water, calculate the freezing point and the boiling point of the solution. Please list each step.
Asked by maham237 @ in Chemistry viewed by 326 People
For a 0.50 molal solution of sucrose in water, calculate the freezing point and the boiling point of the solution. Please list each step.
Answered by maham237 @
We can solve for the freezing point and the boiling point
of the solutions by using the freezing point depression and boiling point
elevation formulas.
ΔTb = Kb m i
ΔTf = Kf m i
where,
Kb and Kf are the boiling point and freezing point
constants for water
Kb = 0.51 °C / molal
Kf = - 1.86 °C / molal
m = molality = 0.50 molal
i = vant Hoff factor = 1
The freezing point and boiling points are:
Freezing point = 0°C + ΔTf
Freezing point = 0°C + (-1.86 °C / molal * 0.5 molal)
Freezing point = - 0.93 °C
Boiling point = 100°C + ΔTb
Boiling point = 100°C + (0.51 °C / molal * 0.5 molal)
Boiling point = 100.255°C
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