Energy required for the ionisation of 0.02 gram atom
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Energy required for ionisation of 0.02 gm atom of magnesium is xKJ . The amount of energy required to ionize 1 atom of magnesium is
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Answer : Energy required to ionize 1 atom of magnesium is 2.02X * 10⁻²¹ kJ
Explanation :
Step 1 : Convert 0.02 g of Mg to mole.
Atomic mass of Mg is 24.3 g/mol
Moles of Mg are 0.000823
Step 2 : Convert mol to number of atoms
We will use Avogadro's value to find number of atoms in 0.00823 mol Mg
According to Avogadro's law, 1 mol of any substance contains 6.02 x 10²³ particles.
Step 3 : Find kJ required for 1 atom
We have been given that the energy required for 4.95 x 10²⁰ atoms is "X" kJ.
Therefore, for 1 atom, the amount of energy is
Energy required to ionize 1 atom of magnesium is 2.02X * 10⁻²¹ kJ
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