Draw the electron configuration for a neutral atom of manganese

Asked by admin @ 05/11/2021 in Chemistry viewed by 297 People

Write the electronic configurations for mn, mn2+, mn4+, mn6+, and mn7+

Answered by admin @ 05/11/2021

Answer: The electronic configurations are written below.

Explanation:

Electronic configuration is defined as the representation of electrons around the nucleus of an atom. Number of electrons in an atom is determined by the atomic number of that atom.

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

We know that:

Atomic number of Manganese = 25 = Number of protons

Number of electrons = Number of protons - charge

For Mn-atom

Number of electrons = 25

Electronic configuration of Mn : $1s^22s^22p^63s^23p^64s^23d^5$

For $Mn^{2+}$ ion:

Number of electron = 25 - (+2) = 23

Electronic configuration of $Mn^{2+}:1s^22s^22p^63s^23p^63d^5$

For $Mn^{4+}$ ion:

Number of electron = 25 - (+4) = 21

Electronic configuration of $Mn^{4+}:1s^22s^22p^63s^23p^63d^3$

For $Mn^{6+}$ ion:

Number of electron = 25 - (+6) = 19

Electronic configuration of $Mn^{6+}:1s^22s^22p^63s^23p^63d^1$

For $Mn^{7+}$ ion:

Number of electron = 25 - (+7) = 18

Electronic configuration of $Mn^{7+}:1s^22s^22p^63s^23p^6$

Hence, the electronic configurations are written above.

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