Determine the empirical formula of an oxide of iron

Asked by admin @ 10/08/2021 in Chemistry viewed by 270 People

Determine the empirical formula of an oxide of iron which has 69.9 % iron and 30.1% dioxygen by mass

Answered by admin @ 10/08/2021

Emperical Formula Of Iron Oxide is Fe2O3

Explanation:

Percent of Fe by mass = 69.9 % [As Given Above]

Percent of O2 by mass = 30.1 % [As Given Above]

Relative moles of Fe in Iron Oxide:

= $\frac{Percent Of Iron By Mass}{Atomic Mass Of Iron}$

= $\frac{69.9}{55.85}$

= 1.25

Relative moles of O in Iron Oxide:

= $\frac{Percent Of Oxygen By Mass}{Atomic Mass Of Oxygen}$

= $\frac{30.1}{16.00}$

= 1.88

Simplest molar ratio of Fe to O:

= 1.25: 1.88

= 1: 1.5

≈ 2:3

Therefore, empirical formula of iron oxide is Fe2O3.

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