Calculate the value of n2 eq if h2
Asked by maham237 @ in Chemistry viewed by 315 People
Calculate the value of [N2]eq if [H2]eq = 2.0 M, [NH3]eq = 0.5 M, and Kc = 2.N2(g) + 3 H2(g) ↔ 2 NH3(g)0.062 M62.5 M0.40 M0.016 M0.031 M
Answered by maham237 @
Answer:
[ N₂(g) ] = 0.016 M
Explanation:
N₂(g) + 3 H₂(g) ↔ 2 NH₃(g)
The equilibrium constant for the above reaction , can be written as the product of the concentration of product raised to the power of stoichiometric coefficients in a balanced equation of dissociation divided by the product of the concentration of reactant raised to the power of stoichiometric coefficients in the balanced equation of dissociation .
Hence ,
Kc = [ NH₃ (g) ]² / [ N₂(g) ] [ H₂(g) ]³
From the question ,
[ NH₃ (g) ] = 0.5 M
[ N₂(g) ] = ?
[ H₂(g) ] = 2.0 M
Kc = 2
Now, putting it in the above equation ,
Kc = [ NH₃ (g) ]² / [ N₂(g) ] [ H₂(g) ]³
2 = [ 0.5 M ]² / [ N₂(g) ] [ 2.0 M ]³
[ N₂(g) ] = 0.016 M .
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