Atoms of element b form hcp lattice and those

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atoms of element B form hcp lattice and those of element a occupy two thirds of tetrahedral voids what is the formula of the compound formed by the elements A and B

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There are totla 6 atoms in hcp lattice... so B = 6

Now , tetrahedral voids will be = 2N = 2*6 = 12 But given , A = 2/3 * 2N = 2/3 * 12 = 8

hence , A = 8 & B=6

so Formula of the compound = A8B6 = A4B3


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