Arrange the following compounds in order of increasing dipole moment


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Arrange the following compounds in order of increasing dipole moment. Toluene (I) m-dichlorobenzene (II) o-dichlorobenzene (III) p-dichlorobenzene (IV)(a) I < IV < II < III (b) IV < I < II < III(c) IV < I < III < II (d) IV < II < I < III

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Answer:

(b) IV < I < II < III is the correct answer.

Explanation:

Toluene is ans aromatic hydrocarbon.

It is also called as tuloul.

It is a mono (single) substituted benzene.

It consists of CH3 group attached to the phenyl ring.

All electrons of benzene are shared equally among carbon.

So it has no net dipole moment.

m dicholoro benzene

It has formula C6H4Cl2.

It is basically 1,3 dichloro benzene.

The dipole moment of m dichloro benzene is high.

It is due to it's symmetrical structure.

o-dichlorobenzene

It has formula C6H4Cl2.

It is basically 1,2 dichloro benzene.

It has higher dipole moment.

It is because elctronegativity of Cl group is greater than that of CH3 group.

It has lower bond angle than m dicholoro benzene.

p- dicholoro benzene.

It has formula C6H4Cl2.

It is basically 1,4 dichloro benzene.

It has zero dipole moment.

It is because of symmetrical structure.

Thus the correct answer is (b) IV < I < II < III


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