Answer : The mole fraction of ethane and ethene in gaseous mixture are, 0.5 and 0.5
Explanation :
First we have to calculate the moles of gaseous mixture of ethane and ethene.
where,
P = pressure of gas = 1 atm
V = volume of gas = 28 L
T = temperature of gas =
n = number of moles of gaseous mixture = ?
R = gas constant = 0.0821 L.atm/mol.K
Now put all the given values in the ideal gas equation, we get:
Thant means,
Let the moles of and be, 'a' and 'b' respectively.
............(1)
The balanced chemical reactions are:
(a)
(b)
From both the reaction, we conclude that
...........(2)
Now by solving the equation 1 and 2, we get:
a = 0.631
b = 0.618
Now we have to calculate the moles fraction of ethane and ethene in gaseous mixture.
Therefore, the mole fraction of ethane and ethene in gaseous mixture are, 0.5 and 0.5