An element has atomic mass 93 and density 11.5
Asked by admin @ in Chemistry viewed by 311 People
An element has atomic mass 93g mol^-1 and density 11.5 g cm^-3. If the edge length of its unit cells is 300pm, identify the tyoe of unit cell
Asked by admin @ in Chemistry viewed by 311 People
An element has atomic mass 93g mol^-1 and density 11.5 g cm^-3. If the edge length of its unit cells is 300pm, identify the tyoe of unit cell
Answered by admin @
Hey !!
Question = An element has atomic mass 93 g mol⁻¹ and density 11.5 g cm⁻³ if the edge length of this unit cell is 300pm identify the type of the unit cell ?
Answer = Number of atoms per unit cell, z = d × a³ × NA / M --> (1)
Here, d = 11.5 g cm⁻³ , M = 93 g mol⁻¹ , NA = 6.022 × 10²³ mol⁻¹
a = 300 pm = 300 × 10⁻¹⁰ cm = 3 × 10⁻⁸ cm
Now, Substituting these values in the expression (1), we get
z = 11.5 g cm⁻³ × (3 × 10⁻⁸ cm)³ × 6.022 × 10²³ mol⁻¹ / 93 g mol⁻¹
FINAL RESULT = 2.01
As there are 2 atoms of the element present unit cell, therefore, the cubic unit cell must be body centered.
Hope it helps you !!
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