An element a burns with golden flame in air

Asked by admin @ 13/08/2021 in Chemistry viewed by 278 People

An element a burns with golden flame in air. it reacts with another element b, atomic number 17 togive a product

c. an aqueous solution of product c on electrolysis gives a compound d andliberates hydrogen. identify a, b, c and
d. also write down the equations for the reactions involved.

Answered by admin @ 13/08/2021

Answer: Element a is Sodium (Na), Element b is Chlorine $(Cl_2)$ , Compound c is Sodium chloride (NaCl) and Compound d is Caustic soda (NaOH).

Explanation:

Element "a" burns with a golden flame in air. Therefore, it is Sodium having formula 'Na'.

Element "b" has an atomic number 17, which is Chlorine $(Cl_2)$ .

Compound "c" is formed when sodium and chlorine react together. The product formed is sodium chloride.

Compound "d" is formed when aqueous solution of sodium chloride, also known as brine solution is electrolysed. This leads to the production of sodium hydroxide, commonly known as caustic soda.

The equations for the above reactions are:

$2Na(s)+Cl_2\rightarrow 2NaCl(s)$

$2NaCl(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)+Cl_2(g)$

An element a burns with golden flame in air

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