A solution of benzoic acid (c6h5cooh) that is 0.20 m has a ph of 2.45. what is ka for benzoic acid?
Asked by maham237 @ in Chemistry viewed by 355 People
Answered by maham237 @
We first calculate for the H+ ion concentration from the pH of the solution of benzoic acid. We do as follows:
pH = -log[H+]
2.45 = -log [H+]
[H+] = 3.55x10^-3
We then use the initial concentration and the h+ ion concentration as follows for Ka calculation:
C6H5COOH = C6H5COO- + H+
I 0.20 0 0
C -x x x
E 0.20-x x x
x = [H+] = 3.55x10^-3
[C6H5COO-] = 3.55x10^-3
[C6H5COOH] = 0.1965
Ka = 3.55x10^-3 (3.55x10^-3) / 0.1965 = 6.42x10^-5
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