A single electron in an ion has ionization energy


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A single electron in an ion head ionisation energy equal to 217.6 eV. What is the total number of neutrons present in one ion of it?

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Ionization energy = 13.6 x z^2
217.6 = 13.6 x z^2
z^2 = 217.6/13.6
z = 4

element = Be
neutrons = 4

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