A certain metal when irradiated with light v 3.2
Asked by admin @ in Chemistry viewed by 289 People
A certain metal when irradiated with light 3.2×10^16 Hz emits photo electrons twice KE
Asked by admin @ in Chemistry viewed by 289 People
A certain metal when irradiated with light 3.2×10^16 Hz emits photo electrons twice KE
Answered by admin @
Explanation:
E(Total Energy) = (Minimum Energy required for the electron) + K.E(kinetic Energy of Photo electron)
On solving, equation (1) and (2), we get,
On substituting, kinetic energy in equation (1), we get,
Thus, the minimum energy is,
Now, the total energy is,
Thus, now the threshold frequency is,
On substituting the found values, we get,
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