1 mole of n2h4 loses 10 moles of electrons


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1 mole of N2H4 lost 10 moles of electrons and formed a new compound,Y in which all hydrogen's are present with out change in the oxidation state. The oxidation number of nitrogen in the new compound Y is

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\huge\underline\mathfrak\purple{Answer}

1 mole N2H4 loses 10mole e-

So, 1 N2H4 loses 10e-

So,  new compound Y=(N2H4)10+

Charge on y is 10+

Let charge on N be x.

2x+4=10

x=+3

\huge\underline\mathfrak\black{Thanks}


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